题解

1 条题解

  • 0
    @ 2019-11-23 15:41:25

    std from xhz

    //std from xhz
    #include<iostream>
    
    int a[1000010];
    
    int main(){
    //  freopen("in0.txt","r",stdin);
    //  freopen("out0.txt","w",stdout);
        int n=0,k=0,s=0;
        scanf("%d",&n);
        for (int i=0;i<n;i++){
            scanf("%d",&a[i]);
            if (i!=0 && a[i]<a[i-1]){
                s=s+a[i-1]-k;
                s=s%100000;
                k=a[i];
            }
        }
        s=s+a[n-1]-k;
        s=s%100000;
        printf("%d",s);
    }
    
  • 1

信息

ID
1029
难度
8
分类
(无)
标签
(无)
递交数
72
已通过
9
通过率
12%
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